Update to gnulib 0.0.7865-a828.
[bpt/guile.git] / lib / malloca.c
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ffca4c22 1/* Safe automatic memory allocation.
af07e104 2 Copyright (C) 2003, 2006-2007, 2009-2013 Free Software Foundation, Inc.
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3 Written by Bruno Haible <bruno@clisp.org>, 2003.
4
5 This program is free software; you can redistribute it and/or modify
6 it under the terms of the GNU Lesser General Public License as published by
7 the Free Software Foundation; either version 2, or (at your option)
8 any later version.
9
10 This program is distributed in the hope that it will be useful,
11 but WITHOUT ANY WARRANTY; without even the implied warranty of
12 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
13 GNU Lesser General Public License for more details.
14
15 You should have received a copy of the GNU Lesser General Public License
005de2e8 16 along with this program; if not, see <http://www.gnu.org/licenses/>. */
ffca4c22 17
dd7d0148 18#define _GL_USE_STDLIB_ALLOC 1
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19#include <config.h>
20
21/* Specification. */
22#include "malloca.h"
23
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24#include <stdint.h>
25
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26#include "verify.h"
27
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28/* The speed critical point in this file is freea() applied to an alloca()
29 result: it must be fast, to match the speed of alloca(). The speed of
30 mmalloca() and freea() in the other case are not critical, because they
31 are only invoked for big memory sizes. */
32
33#if HAVE_ALLOCA
34
35/* Store the mmalloca() results in a hash table. This is needed to reliably
36 distinguish a mmalloca() result and an alloca() result.
37
38 Although it is possible that the same pointer is returned by alloca() and
39 by mmalloca() at different times in the same application, it does not lead
40 to a bug in freea(), because:
41 - Before a pointer returned by alloca() can point into malloc()ed memory,
42 the function must return, and once this has happened the programmer must
43 not call freea() on it anyway.
44 - Before a pointer returned by mmalloca() can point into the stack, it
45 must be freed. The only function that can free it is freea(), and
46 when freea() frees it, it also removes it from the hash table. */
47
48#define MAGIC_NUMBER 0x1415fb4a
49#define MAGIC_SIZE sizeof (int)
50/* This is how the header info would look like without any alignment
51 considerations. */
52struct preliminary_header { void *next; char room[MAGIC_SIZE]; };
53/* But the header's size must be a multiple of sa_alignment_max. */
54#define HEADER_SIZE \
55 (((sizeof (struct preliminary_header) + sa_alignment_max - 1) / sa_alignment_max) * sa_alignment_max)
56struct header { void *next; char room[HEADER_SIZE - sizeof (struct preliminary_header) + MAGIC_SIZE]; };
0f00f2c3 57verify (HEADER_SIZE == sizeof (struct header));
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58/* We make the hash table quite big, so that during lookups the probability
59 of empty hash buckets is quite high. There is no need to make the hash
60 table resizable, because when the hash table gets filled so much that the
61 lookup becomes slow, it means that the application has memory leaks. */
62#define HASH_TABLE_SIZE 257
63static void * mmalloca_results[HASH_TABLE_SIZE];
64
65#endif
66
67void *
68mmalloca (size_t n)
69{
70#if HAVE_ALLOCA
71 /* Allocate one more word, that serves as an indicator for malloc()ed
72 memory, so that freea() of an alloca() result is fast. */
73 size_t nplus = n + HEADER_SIZE;
74
75 if (nplus >= n)
76 {
77 char *p = (char *) malloc (nplus);
78
79 if (p != NULL)
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80 {
81 size_t slot;
ffca4c22 82
1cd4fffc 83 p += HEADER_SIZE;
ffca4c22 84
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85 /* Put a magic number into the indicator word. */
86 ((int *) p)[-1] = MAGIC_NUMBER;
ffca4c22 87
1cd4fffc 88 /* Enter p into the hash table. */
005de2e8 89 slot = (uintptr_t) p % HASH_TABLE_SIZE;
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90 ((struct header *) (p - HEADER_SIZE))->next = mmalloca_results[slot];
91 mmalloca_results[slot] = p;
ffca4c22 92
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93 return p;
94 }
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95 }
96 /* Out of memory. */
97 return NULL;
98#else
99# if !MALLOC_0_IS_NONNULL
100 if (n == 0)
101 n = 1;
102# endif
103 return malloc (n);
104#endif
105}
106
107#if HAVE_ALLOCA
108void
109freea (void *p)
110{
111 /* mmalloca() may have returned NULL. */
112 if (p != NULL)
113 {
114 /* Attempt to quickly distinguish the mmalloca() result - which has
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115 a magic indicator word - and the alloca() result - which has an
116 uninitialized indicator word. It is for this test that sa_increment
117 additional bytes are allocated in the alloca() case. */
ffca4c22 118 if (((int *) p)[-1] == MAGIC_NUMBER)
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119 {
120 /* Looks like a mmalloca() result. To see whether it really is one,
121 perform a lookup in the hash table. */
005de2e8 122 size_t slot = (uintptr_t) p % HASH_TABLE_SIZE;
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123 void **chain = &mmalloca_results[slot];
124 for (; *chain != NULL;)
125 {
126 if (*chain == p)
127 {
128 /* Found it. Remove it from the hash table and free it. */
129 char *p_begin = (char *) p - HEADER_SIZE;
130 *chain = ((struct header *) p_begin)->next;
131 free (p_begin);
132 return;
133 }
134 chain = &((struct header *) ((char *) *chain - HEADER_SIZE))->next;
135 }
136 }
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137 /* At this point, we know it was not a mmalloca() result. */
138 }
139}
140#endif