source/Mask.C

   1 // Mask.C  -*- C++ -*-
   2 // Copyright (c) 1997, 1998 Etienne BERNARD
   3
   4 // This program is free software; you can redistribute it and/or modify
   5 // it under the terms of the GNU General Public License as published by
   6 // the Free Software Foundation; either version 2 of the License, or
   7 // any later version.
   8
   9 // This program is distributed in the hope that it will be useful,
  10 // but WITHOUT ANY WARRANTY; without even the implied warranty of
  11 // MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
  12 // GNU General Public License for more details.
  13
  14 // You should have received a copy of the GNU General Public License
  15 // along with this program; if not, write to the Free Software
  16 // Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA  02110-1301, USA.
  17
  18 #include <string.h>
  19
  20 #include "Mask.H"
  21
  22 Mask::Mask(String s)
  23   : mask(s)
  24 { }
  25
  26 String
  27 Mask::getMask() const
  28 {
  29   return mask;
  30 }
  31
  32 bool
  33 Mask::matches(String s) const
  34 {
  35   return match((const char *)mask, (const char *)s);
  36 }
  37
  38 bool
  39 Mask::matches(const Mask & m) const
  40 {
  41   return match((const char *)mask, (const char *)m.mask);
  42 }
  43
  44 bool
  45 Mask::match(const char * m, const char * n) const
  46 {
  47   if (!*m) {
  48     if (!*n)
  49       return true;
  50     else
  51       return false;
  52   } else
  53     if (!*n)
  54       return false;
  55
  56   if (m[0] == '*') {
  57     while (*m && (m[0] == '*' || m[0] == '?'))
  58       m++;
  59
  60     if (*m == '\0')
  61       return true;
  62
  63     const char *c = n;
  64     while ((c = strchr(c, *m)) != 0) {
  65       if (match(m, c))
  66         return 1;
  67       c++;
  68     }
  69   }
  70
  71   if ((std::tolower (m[0]) == std::tolower (n[0])) ||
  72       (m[0] == '?') ||
  73       ((m[0] == '\\') && ((m[1] == '?' && n[0] == '?') ||
  74                           (m[1] == '*' && n[0] == '*'))))
  75     return match(++m, ++n);
  76
  77   return false;
  78 }